A gas with a volume of 4.0 L at a pressure of 205 kPa is allowed to expand to a volume of 12.0 L. What is the pressure in the container if the temperature remains constant?

Question

A gas with a volume of 4.0 L at a pressure of 205 kPa is allowed to expand to a volume of 12.0 L. What is the pressure in the container if the temperature remains constant?

1 Answer

Impact of this question

74164 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-01T10:07:43

We use old $Boyle's Law$ $"Boyle's Law"$ , $P V = k,$ $PV=k,$ where $k$ $k$ is a $constant$ $"constant"$ .

Explanation:

And the utility of this law means that we could use non-standard units, if our units are consistent.

Given that $P V = k,$ $PV=k,$ (temperature constant), it follows that...........

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ ..........

We solve for $P_2=(P_1V_1)/(V_2)=(205*kPaxx4.0*cancelL)/(12.0*cancelL)$

$~=68*kPa$

The pressure has reasonably decreased............Why $"reasonably?"$ And given consistent units, I could use $"pints"$ , $"foot lbs"$ , $"atmospheres"$ whatever...........

Science

Math

Humanities

... and beyond

A gas with a volume of 4.0 L at a pressure of 205 kPa is allowed to expand to a volume of 12.0 L. What is the pressure in the container if the temperature remains constant?

1 Answer

Explanation:

Related questions

Impact of this question