A glass marble projected horizontally from the top of a table Falls at a distance x from the edge of the table if h is the height of the table then the velocity of projection is?

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Answer 1 · 2018-03-24T06:36:49

The velocity of projection is #=x*sqrt((g)/(2h))ms^-1#

Let the horizontal velocity of projection be #=vms^-1#

The height of the table is #=hm#

The acceletation due to gravity is #g=9.8ms^-2#

Applying the equation of motion

#s=ut+1/2at^2#

The vertical component is #u=0ms^-1#

#h=0+1/2g t ^2#

#t=sqrt((2h)/(g))#

The horizontal distance is #)xm#

Therefore,

#x=v*sqrt((2h)/(g))#

#v=x*sqrt((g)/(2h))#