A line passes through (3,4) and (4,7). A second line passes through (7,3). What is one other point that the second line may pass through if it is parallel to the first line?

1 Answer
Jul 27, 2017

See a solution process below:

Explanation:

First, we need to calculate the slope of the first line: m1. The slope can be found by using the formula: m=y2y1x2x1

Where m is the slope and (x1,y1) and (x2,y2) are the two points on the line.

Substituting the values from the points in the problem gives:

m1=7443=31

Because the two lines are parallel, the slope of the second line will also be 31. We can call the slope of the second line m2

Substituting the values from the one point and the slope we calculated for the first line gives:

m2=y3x7

31=y3x7

We can now solve these two equations to get another point on the second line:

- Solve for the Numerator:

y3=3

y3+3=3+3

y0=6

y=6

- Solve for the Denominator:

x7=1

x0=8

One other point on the second line is: (8,6)