A line passes through $(4 ,3 )$ and $(7 ,1 )$ . A second line passes through $(1 ,8 )$ . What is one other point that the second line may pass through if it is parallel to the first line?

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Answer 1 · 2016-05-29T13:53:46

Find the slope of the first line, then apply it to the point of the second line to find $(1+3,8-2)=(4,6)$

We can solve this by finding the slope of the first line, then applying that slope to the point of the second line.

The first line passes through points $(4,3) and (7,1)$ . Let's determine the slope.

The equation of slope is $m=(y_2-y_1)/(x_2-x_1)$ . Let's plug in our points into this equation:

$m=(1-3)/(7-4)=-2/3$

We can now apply this slope to point $(1,8)$ . I'll move 3 to the right on the x axis and 2 down on the y:

$(1+3,8-2)=(4,6)$

A line passes through (4 ,3 )(4 ,3 ) and (7 ,1 )(7 ,1 ). A second line passes through (1 ,8 )(1 ,8 ). What is one other point that the second line may pass through if it is parallel to the first line?