A line passes through (5,9) and (8,3). A second line passes through (3,6). What is one other point that the second line may pass through if it is parallel to the first line?

1 Answer
May 15, 2016

Any point lying on 2x+y=12, will satisfy this condition. One such point is (9,30)

Explanation:

The slope of line passing through (x1,y1) and (x2,y2) is given by y2y1x2x1,

Hence slope of line joining (5,9) and (8,3) is 3985=63=2

Slope of a line parallel to this line will also be 2 and using point slope form of equation the equation of line passing through (3,6) and a slope of 2 is

(y6)=(2)(x3) or y6=2x+6 or 2x+y=12

Hence any point lying on 2x+y=12, will satisfy this condition.

Let us put x=9 then 18+y=12 or y=30

Hence one such point is (9,30)