A line passes through (8,2) and (2,1). A second line passes through (3,5). What is one other point that the second line may pass through if it is parallel to the first line?

1 Answer
Mar 20, 2016

(9,6)

Explanation:

The first step is to calculate the gradient of the line passing through the 2 given points, using the gradient formula

m=y2y1x2x1

where (x1,y1) and (x2,y2) are 2 coordinate points

let (x1,y1)=(8,2) and (x2,y2)=(2,1)

hence m=1228=16=16

The second line is parallel and will also have m=16

There will be an infinite number of points along with (3,5) which will have the same gradient. To find a point (add 1 to y-coord and 6 to x-coord) From definition of gradient.

(3+6,5+1)=(9,6)(15,7) is another point