A line passes through (8,2) and (2,1). A second line passes through (3,5). What is one other point that the second line may pass through if it is parallel to the first line?
1 Answer
Mar 20, 2016
(9,6)
Explanation:
The first step is to calculate the gradient of the line passing through the 2 given points, using the
gradient formula
m=y2−y1x2−x1 where
(x1,y1) and (x2,y2) are 2 coordinate points let
(x1,y1)=(8,2) and (x2,y2)=(2,1) hence
m=1−22−8=−1−6=16 The second line is parallel and will also have
m=16 There will be an infinite number of points along with (3,5) which will have the same gradient. To find a point (add 1 to y-coord and 6 to x-coord) From definition of gradient.
⇒(3+6,5+1)=(9,6)→(15,7) is another point