A lunch pail is accidentally kicked off a steel beam on a building under construction. Suppose the initial horizontal speed is 1.50 m/s. How far does the lunch pail fall after it travels 3.50 m horizontally?

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Answer 1 · 2015-11-26T01:21:30

#26.7"m"#

The horizontal component of the velocity is constant so we can get the time of flight from:

#v=s/t#

#:.t=s/v=3.5/1.5=2.33"s"#

Now we can consider its vertical motion:

#s=1/2"g"t^2#

#:.s=1/2xx9.8xx2.33^2=26.7"m"#