A metallic element $X$ $X$ forms a carbonate with the formula $X {(C O_{3})}_{2}$ $X(CO_3)_2$ . What would the corresponding formula be of the fluoride compound of element $X$ $X$ ?

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A metallic element $X$ $X$ forms a carbonate with the formula $X {(C O_{3})}_{2}$ $X(CO_3)_2$ . What would the corresponding formula be of the fluoride compound of element $X$ $X$ ?

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Answer 1 · 2017-01-05T22:37:41

$X F_{4}$ $XF_4$

Explanation:

The starting species is $X {(C O_{3})}_{2}$ $X(CO_3)_2$ . And thus, separating the ions, we get $X^{4 +}$ $X^(4+)$ and $2 \times C O_{3}^{2 -}$ $2xxCO_3^(2-)$ .

Fluorine is an excellent oxidant and gives $F^{-}$ $F^-$ ions upon reduction, so to preserve electrical neutrality we get $X F_{4}$ $XF_4$ .

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A metallic element $X$ $X$ forms a carbonate with the formula $X {(C O_{3})}_{2}$ $X(CO_3)_2$ . What would the corresponding formula be of the fluoride compound of element $X$ $X$ ?

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Explanation:

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A metallic element XX forms a carbonate with the formula X(CO3)2X(CO_3)_2. What would the corresponding formula be of the fluoride compound of element XX?

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Explanation:

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A metallic element $X$ $X$ forms a carbonate with the formula $X {(C O_{3})}_{2}$ $X(CO_3)_2$ . What would the corresponding formula be of the fluoride compound of element $X$ $X$ ?