A model train with a mass of $1 kg$ is moving along a track at $24 (cm)/s$ . If the curvature of the track changes from a radius of $16 cm$ to $15 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-05-31T06:32:49

The centripetal force changes by $=0.024N$

The centripetal force is

$F=(mv^2)/r$

mass, $m=1kg$

speed, $v=0.24ms^-1$

radius, $=(r) m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=1*0.24^2/0.16=0.36N$

$F_2=mv^2/r_2=1*0.24^2/0.15=0.384N$

$DeltaF=0.384-0.36=0.024N$

A model train with a mass of 1 kg1 kg is moving along a track at 24 (cm)/s24 (cm)/s. If the curvature of the track changes from a radius of 16 cm16 cm to 15 cm15 cm, by how much must the centripetal force applied by the tracks change?