A model train with a mass of 1 kg is moving along a track at 24 (cm)/s. If the curvature of the track changes from a radius of 72 cm to 150 cm, by how much must the centripetal force applied by the tracks change?

1 Answer
Feb 28, 2017

The change in centripetal force is =0.0416N

Explanation:

The centripetal force is

F=(mv^2)/r

m=mass=1kg

v=0.24ms^-1

The variation in centripetal force is

DeltaF=F_2-F_1

F_1=1*0.24^2/0.72=N

F_2=1*0.24^2/1.5=N

DeltaF=0.08-0.0384=0.0416N