A model train with a mass of $1 kg$ is moving along a track at $24 (cm)/s$ . If the curvature of the track changes from a radius of $72 cm$ to $180 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2018-04-06T19:43:44

The change in centripetal force is $=0.048N$

The centripetal force is

$vecF_C=(mv^2)/r*vecr$

The mass is of the train $m=1kg$

The velocity of the train is $v=0.24ms^-1$

The radii of the tracks are

$r_1=0.72m$

and

$r_2=1.80m$

The variation in the centripetal force is

$DeltaF=F_2-F_1$

The centripetal forces are

$||F_1||=1*0.24^2/0.72=0.08N$

$||F_2||=1*0.24^2/1.80=0.032N$

$DeltaF=F_1-F_2=0.08-0.0032=0.048N$

A model train with a mass of 1 kg1 kg is moving along a track at 24 (cm)/s24 (cm)/s. If the curvature of the track changes from a radius of 72 cm72 cm to 180 cm180 cm, by how much must the centripetal force applied by the tracks change?