A model train with a mass of $1 k g$ $1 kg$ is moving along a track at $24 \frac{c m}{s}$ $24 (cm)/s$ . If the curvature of the track changes from a radius of $96 c m$ $96 cm$ to $180 c m$ $180 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2016-04-25T02:06:34

$\frac{F 1}{F 2} = \frac{r 2}{r 1}$ $(F1)/(F2)=(r2)/(r1)$
$F 1 = \frac{96}{180} F 2$ $F1=96/180F2$

Centripetal force,
$F = \frac{m v^{2}}{r}$ $F=(mv^2)/r$
F is inversely proportional to r , where r = radius of the track

A model train with a mass of 1kg1 kg is moving along a track at 24cms24 (cm)/s. If the curvature of the track changes from a radius of 96cm96 cm to 180cm180 cm, by how much must the centripetal force applied by the tracks change?