A model train with a mass of $1 kg$ is moving along a track at $24 (cm)/s$ . If the curvature of the track changes from a radius of $96 cm$ to $360 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-05-18T05:59:54

The change in centripetal force is $=0.044N$

The centripetal force is

$F=(mv^2)/r$

mass, $m=1kg$

speed, $v=0.24ms^-1$

radius, $=(r) m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=1*0.24^2/0.96=0.06N$

$F_2=mv^2/r_2=1*0.24^2/3.60=0.016N$

$DeltaF=0.06-0.016=0.044N$

A model train with a mass of 1 kg1 kg is moving along a track at 24 (cm)/s24 (cm)/s. If the curvature of the track changes from a radius of 96 cm96 cm to 360 cm360 cm, by how much must the centripetal force applied by the tracks change?