A model train with a mass of $1 k g$ $1 kg$ is moving along a track at $24 \frac{c m}{s}$ $24 (cm)/s$ . If the curvature of the track changes from a radius of $144 c m$ $144 cm$ to $360 c m$ $360 cm$ , by how much must the centripetal force applied by the tracks change?

Question

1434 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-10T08:10:51

The change i centripetal force is $0.024 N$ $0.024N$

The centripetal force is

$F = \frac{m v^{2}}{r}$ $F=(mv^2)/r$

The mass is of the train $m = 1 k g$ $m=1kg$

The velocity of the train is $v = 0.24 m s^{- 1}$ $v=0.24ms^-1$

The radii are

$r_{1} = 1.44 m$ $r_1=1.44m$

and

$r_{2} = 3.60 m$ $r_2=3.60m$

The variation in the centripetal force is

$DeltaF=F_2-F_1$

The centripetal forces are

$F_1=1*0.24^2/1.44=0.04N$

$F_2=1*0.24^2/3.60=0.016N$

$DeltaF=0.04-0.016=0.024N$

A model train with a mass of 1 kg1kg1 kg is moving along a track at 24 (cm)/s24cms24 (cm)/s. If the curvature of the track changes from a radius of 144 cm144cm144 cm to 360 cm360cm360 cm, by how much must the centripetal force applied by the tracks change?