A model train, with a mass of 12 kg12kg, is moving on a circular track with a radius of 9 m9m. If the train's rate of revolution changes from 5 Hz5Hz to 9 Hz9Hz, by how much will the centripetal force applied by the tracks change by?

1 Answer
Apr 30, 2017

The centripetal force changes by =68218.7N=68218.7N

Explanation:

The centripetal force is

F=mr omega^2F=mrω2

mass is m=12kgm=12kg

radius r=9mr=9m

Delta omega=(9-5)*2pi=(8pi)rads^-1

The variation in centripetal force is

DeltaF=mr(Delta omega)^2

=12*9*(8pi)^2

=68218.7N