A model train, with a mass of $12 kg$ , is moving on a circular track with a radius of $9 m$ . If the train's rate of revolution changes from $5 Hz$ to $8 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-06-29T09:55:24

The centripetal force changes by $=38.373kN$

The centripetal force is

$F=mr omega^2$

The mass is $m=12kg$

The radius $r=9m$

The change in angular velocity is

$Delta omega=(8-5)*2pi=(6pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=12*9*(6pi)^2$

$=38373N$

A model train, with a mass of 12 kg12 kg, is moving on a circular track with a radius of 9 m9 m. If the train's rate of revolution changes from 5 Hz5 Hz to 8 Hz8 Hz, by how much will the centripetal force applied by the tracks change by?