A model train, with a mass of $12 k g$ $12 kg$ , is moving on a circular track with a radius of $6 m$ $6 m$ . If the train's kinetic energy changes from $81 j$ $81 j$ to $24 j$ $24 j$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-06-27T06:07:03

The change in centripetal force is $= 19 N$ $=19N$

The centripetal force is

$F = \frac{m v^{2}}{r}$ $F=(mv^2)/r$

The kinetic energy is

$K E = \frac{1}{2} m v^{2}$ $KE=1/2mv^2$

The variation of kinetic energy is

$Delta KE=1/2mv^2-1/2m u^2$

$=1/2m(v^2-u^2)$

The radius is $=6m$

The variation of centripetal force is

$DeltaF=m/r(v^2-u^2)$

$DeltaF=2m/r1/2(v^2-u^2)$

$=(2)/r*1/2m(v^2-u^2)$

$=(2)/r*Delta KE$

$=2/6*(81-24)N$

$=19N$

A model train, with a mass of 12 kg12kg12 kg, is moving on a circular track with a radius of 6 m6m6 m. If the train's kinetic energy changes from 81 j81j81 j to 24 j24j24 j, by how much will the centripetal force applied by the tracks change by?