A model train, with a mass of $12 kg$ , is moving on a circular track with a radius of $9 m$ . If the train's kinetic energy changes from $36 j$ to $18 j$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-07-02T07:45:28

The centripetal force changes by $=4N$

The centripetal force is

$F=(mv^2)/r$

The kinetic energy is

$KE=1/2mv^2$

The variation of kinetic energy is

$Delta KE=1/2mv^2-1/2m u^2$

$=1/2m(v^2-u^2)$

The radius is $=9m$

The variation of centripetal force is

$DeltaF=m/r(v^2-u^2)$

$DeltaF=2m/r1/2(v^2-u^2)$

$=(2)/r*1/2m(v^2-u^2)$

$=(2)/r*Delta KE$

$=2/9*(36-18)N$

$=4N$

A model train, with a mass of 12 kg12 kg, is moving on a circular track with a radius of 9 m9 m. If the train's kinetic energy changes from 36 j36 j to 18 j18 j, by how much will the centripetal force applied by the tracks change by?