A model train, with a mass of $12 k g$ $12 kg$ , is moving on a circular track with a radius of $1 m$ $1 m$ . If the train's rate of revolution changes from $6 H z$ $6 Hz$ to $4 H z$ $4 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-03-03T14:20:26

The centripetal force is $= 1895 N$ $=1895N$

The centripetal force is

$F = m r ω^{2}$ $F=mr omega^2$

$m = 12 k g$ $m=12kg$

$r = 1 m$ $r=1m$

$Delta omega=(6-4)*2pi=4pirads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=12*1*(4pi)^2$

$=12*16*pi^2$

$=1895N$

A model train, with a mass of 12 kg12kg12 kg, is moving on a circular track with a radius of 1 m1m1 m. If the train's rate of revolution changes from 6 Hz6Hz6 Hz to 4 Hz4Hz4 Hz, by how much will the centripetal force applied by the tracks change by?