A model train with a mass of $2 k g$ $2 kg$ is moving along a track at $15 \frac{c m}{s}$ $15 (cm)/s$ . If the curvature of the track changes from a radius of $9 c m$ $9 cm$ to $12 c m$ $12 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2018-01-17T06:20:59

The change in centripetal force is $= 0.125 N$ $=0.125N$

The centripetal force is

$F = \frac{m v^{2}}{r}$ $F=(mv^2)/r$

The mass is of the train $m = 2 k g$ $m=2kg$

The velocity of the train is $v = 0.15 m s^{- 1}$ $v=0.15ms^-1$

The radii are

$r_{1} = 0.09 m$ $r_1=0.09m$

and

$r_{2} = 0.12 m$ $r_2=0.12m$

The variation in the centripetal force is

$DeltaF=F_2-F_1$

The centripetal forces are

$F_1=2*0.15^2/0.09=0.5N$

$F_2=2*0.15^2/0.12=0.375N$

$DeltaF=F_1-F_2=0.5-0.375=0.125N$

A model train with a mass of 2 kg2kg2 kg is moving along a track at 15 (cm)/s15cms15 (cm)/s. If the curvature of the track changes from a radius of 9 cm9cm9 cm to 12 cm12cm12 cm, by how much must the centripetal force applied by the tracks change?