A model train with a mass of $2 k g$ $2 kg$ is moving along a track at $15 \frac{c m}{s}$ $15 (cm)/s$ . If the curvature of the track changes from a radius of $5 c m$ $5 cm$ to $12 c m$ $12 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2016-04-16T04:29:31

Change in force $= 52, 500$ $=52,500" "$ Dynes

Force at radius $r_{1} = 5$ $r_1=5$

$F_{1} = m \frac{v^{2}}{r_{1}} = 2000 \frac{{(15)}^{2}}{5} = 90000$ $F_1=mv^2/r_1=2000(15)^2/5=90000 " "$ Dynes

Force at radius $r_{2} = 12$ $r_2=12$

$F_{2} = m \frac{v^{2}}{r_{2}} = 2000 \frac{{(15)}^{2}}{12} = 37500$ $F_2=mv^2/r_2=2000(15)^2/12=37500 " "$ Dynes

Change in force $= F_{1} - F_{2} = 90000 - 37500 = 52500$ $=F_1-F_2=90000-37500=52500" "$ Dynes

God bless....I hope the explanation is useful.

A model train with a mass of 2kg2 kg is moving along a track at 15cms15 (cm)/s. If the curvature of the track changes from a radius of 5cm5 cm to 12cm12 cm, by how much must the centripetal force applied by the tracks change?