A model train with a mass of $2 k g$ $2 kg$ is moving along a track at $18 \frac{c m}{s}$ $18 (cm)/s$ . If the curvature of the track changes from a radius of $9 c m$ $9 cm$ to $3 c m$ $3 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-07-22T05:50:07

The change in centripetal force is $= 1.44 N$ $=1.44N$

The centripetal force is

$F = \frac{m v^{2}}{r}$ $F=(mv^2)/r$

The mass is $m = 2 k g$ $m=2kg$

The speed is $v = 0.18 m s^{- 1}$ $v=0.18ms^-1$

The radius is $= (r) m$ $=(r) m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=2*0.18^2/0.09=0.72N$

$F_2=mv^2/r_2=2*0.18^2/0.03=2.16N$

$DeltaF=2.16-0.72=1.44N$

A model train with a mass of 2 kg2kg2 kg is moving along a track at 18 (cm)/s18cms18 (cm)/s. If the curvature of the track changes from a radius of 9 cm9cm9 cm to 3 cm3cm3 cm, by how much must the centripetal force applied by the tracks change?