A model train with a mass of $2 k g$ $2 kg$ is moving along a track at $2 \frac{c m}{s}$ $2 (cm)/s$ . If the curvature of the track changes from a radius of $7 c m$ $7 cm$ to $12 c m$ $12 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-04-01T06:39:37

The change in centripetal force is $= 0.004 N$ $=0.004N$

The centripetal force is

$F = \frac{m v^{2}}{r}$ $F=(mv^2)/r$

mass, $m = 2 k g$ $m=2kg$

speed, $v = 0.02 m s^{- 1}$ $v=0.02ms^-1$

radius, $= r$ $=r$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=2*0.02^2/0.07=0.011N$

$F_2=2*0.02^2/0.12=0.0067N$

$DeltaF=0.011-0.0067=0.004N$

A model train with a mass of 2 kg2kg2 kg is moving along a track at 2 (cm)/s2cms2 (cm)/s. If the curvature of the track changes from a radius of 7 cm7cm7 cm to 12 cm12cm12 cm, by how much must the centripetal force applied by the tracks change?