A model train with a mass of 2 kg is moving along a track at 2 (cm)/s. If the curvature of the track changes from a radius of 7 cm to 1 cm, by how much must the centripetal force applied by the tracks change?

1 Answer
May 10, 2018

The change in centripetal force is =0.0686N

Explanation:

The centripetal force is

vecF_C=(mv^2)/r*vecr

The mass is of the train m=2kg

The velocity of the train is v=0.02ms^-1

The radii of the tracks are

r_1=0.07m

and

r_2=0.01m

The variation in the centripetal force is

DeltaF=F_2-F_1

The centripetal forces are

||F_1||=2*0.02^2/0.07=0.0114N

||F_2||=2*0.02^2/0.01=0.08N

DeltaF=|F_1-F_2|=0.08-0.0114=0.0686N