A model train with a mass of $2 k g$ $2 kg$ is moving along a track at $2 \frac{c m}{s}$ $2 (cm)/s$ . If the curvature of the track changes from a radius of $3 c m$ $3 cm$ to $1 c m$ $1 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-08-12T16:32:38

The change in centripetal force is $= 0.053 N$ $=0.053N$

The centripetal force is

$F = \frac{m v^{2}}{r}$ $F=(mv^2)/r$

The mass, $m = (2) k g$ $m=(2)kg$

The speed, $v = (0.02) m s^{- 1}$ $v=(0.02)ms^-1$

The radius, $= (r) m$ $=(r) m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=2*0.02^2/0.03=0.027N$

$F_2=mv^2/r_2=2*0.02^2/0.01=0.08N$

$DeltaF=0.08-0.027=0.053N$

A model train with a mass of 2 kg2kg2 kg is moving along a track at 2 (cm)/s2cms2 (cm)/s. If the curvature of the track changes from a radius of 3 cm3cm3 cm to 1 cm1cm1 cm, by how much must the centripetal force applied by the tracks change?