A model train with a mass of $2 kg$ is moving along a track at $3 (cm)/s$ . If the curvature of the track changes from a radius of $6 cm$ to $12 cm$ , by how much must the centripetal force applied by the tracks change?

Question

1364 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-11T11:59:51

The centripetal force changes by $=0.015N$

The centripetal force is

$F=(mv^2)/r$

mass, $m=2kg$

speed, $v=0.03ms^-1$

radius, $=(r) m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=2*0.03^2/0.06=0.03N$

$F_2=mv^2/r_2=2*0.03^2/0.12=0.015N$

$DeltaF=0.03-0.015=0.015N$

A model train with a mass of 2 kg2 kg is moving along a track at 3 (cm)/s3 (cm)/s. If the curvature of the track changes from a radius of 6 cm6 cm to 12 cm12 cm, by how much must the centripetal force applied by the tracks change?