A model train with a mass of $2 kg$ is moving along a track at $36 (cm)/s$ . If the curvature of the track changes from a radius of $9 cm$ to $3 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-03-25T10:56:10

The change in centripetal force is $=5.76N$

The centripetal force is

$F=(mv^2)/r$

$m=mass=2kg$

$v=0.36ms^-1$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=2*0.36^2/0.09=2.88N$

$F_2=2*0.36^2/0.03=8.64N$

$DeltaF=8.64-2.88=5.76N$

A model train with a mass of 2 kg2 kg is moving along a track at 36 (cm)/s36 (cm)/s. If the curvature of the track changes from a radius of 9 cm9 cm to 3 cm3 cm, by how much must the centripetal force applied by the tracks change?