A model train with a mass of $2 kg$ is moving along a track at $6 (cm)/s$ . If the curvature of the track changes from a radius of $12 cm$ to $8 cm$ , by how much must the centripetal force applied by the tracks change?

Question

1426 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-02T07:09:59

The change in centripetal force is $=0.03N$

The centripetal force is

$vecF_C=(mv^2)/r*vecr$

The mass is of the train $m=2kg$

The velocity of the train is $v=0.06ms^-1$

The radii of the tracks are

$r_1=0.12m$

and

$r_2=0.08m$

The variation in the centripetal force is

$DeltaF=F_2-F_1$

The centripetal forces are

$||F_1||=2*0.06^2/0.12=0.06N$

$||F_2||=2*0.06^2/0.08=0.09N$

$DeltaF=F_2-F_1=0.09-0.06=0.03N$

A model train with a mass of 2 kg2 kg is moving along a track at 6 (cm)/s6 (cm)/s. If the curvature of the track changes from a radius of 12 cm12 cm to 8 cm8 cm, by how much must the centripetal force applied by the tracks change?