A model train with a mass of $2 kg$ is moving along a track at $9 (cm)/s$ . If the curvature of the track changes from a radius of $5 cm$ to $24 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-08-23T18:00:58

The change in centripetal force is $=0.2565N$

The centripetal force is

$F=(mv^2)/r$

The mass, $m=(2)kg$

The speed, $v=(0.09)ms^-1$

The radius, $=(r) m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=2*0.09^2/0.05=0.324N$

$F_2=mv^2/r_2=2*0.09^2/0.24=0.015N$

$DeltaF=0.324-0.0675=0.2565N$

A model train with a mass of 2 kg2 kg is moving along a track at 9 (cm)/s9 (cm)/s. If the curvature of the track changes from a radius of 5 cm5 cm to 24 cm24 cm, by how much must the centripetal force applied by the tracks change?