A model train with a mass of $2 kg$ is moving along a track at $9 (cm)/s$ . If the curvature of the track changes from a radius of $6 cm$ to $3 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-06-18T09:51:59

The centripetal force changes by $=0.27N$

The centripetal force is

$F=(mv^2)/r$

mass, $m=2kg$

speed, $v=0.09ms^-1$

radius, $=(r) m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=2*0.09^2/0.06=0.27N$

$F_2=mv^2/r_2=2*0.09^2/0.03=0.54N$

$DeltaF=0.54-0.27=0.27N$

A model train with a mass of 2 kg2 kg is moving along a track at 9 (cm)/s9 (cm)/s. If the curvature of the track changes from a radius of 6 cm6 cm to 3 cm3 cm, by how much must the centripetal force applied by the tracks change?