A model train, with a mass of $2 k g$ $2 kg$ , is moving on a circular track with a radius of $4 m$ $4 m$ . If the train's rate of revolution changes from $\frac{1}{4} H z$ $1/4 Hz$ to $\frac{2}{5} H z$ $2/5 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-08-22T05:45:53

The change in centripetal force is $= 7.11 N$ $=7.11N$

The centripetal force is

$F = m r ω^{2}$ $F=mr omega^2$

The mass is $m = 2 k g$ $m=2kg$

The radius $r = 4 m$ $r=4m$

The change in angular velocity is

$Delta omega=(2/5-1/4)*2pi=(3/10pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=2*4*(3/10pi)^2$

$=7.11N$

A model train, with a mass of 2 kg2kg2 kg, is moving on a circular track with a radius of 4 m4m4 m. If the train's rate of revolution changes from 1/4 Hz14Hz1/4 Hz to 2/5 Hz25Hz2/5 Hz, by how much will the centripetal force applied by the tracks change by?