A model train, with a mass of $2 kg$ , is moving on a circular track with a radius of $9 m$ . If the train's rate of revolution changes from $5 Hz$ to $2 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2018-04-05T08:51:38

The change in centripetal force is $=14922.9N$

The centripetal force is

$F=(mv^2)/r=mromega^2N$

The mass of the train, $m=(2)kg$

The radius of the track, $r=(9)m$

The frequencies are

$f_1=(5)Hz$

$f_2=(2)Hz$

The angular velocity is $omega=2pif$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mromega_1^2=mr*(2pif_1)^2=2*9*(2pi*5)^2=17765.3N$

$F_2=mromega_2^2=mr*(2pif_2)^2=2*9*(2pi*2)^2=2842.4N$

$DeltaF=F_2-F_1=17765.3-2842.4=14922.9N$

A model train, with a mass of 2 kg2 kg, is moving on a circular track with a radius of 9 m9 m. If the train's rate of revolution changes from 5 Hz5 Hz to 2 Hz2 Hz, by how much will the centripetal force applied by the tracks change by?