A model train, with a mass of $2 kg$ , is moving on a circular track with a radius of $4 m$ . If the train's rate of revolution changes from $1/2 Hz$ to $2/8 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-02-23T06:58:59

The centripetal force change by $=19.74N$

The centripetal force is

$F=mr omega^2$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=2*4*((1/2-1/4)2pi)^2$

$=8*4/16*pi^2=2pi^2$

$=19.74N$

A model train, with a mass of 2 kg2 kg, is moving on a circular track with a radius of 4 m4 m. If the train's rate of revolution changes from 1/2 Hz1/2 Hz to 2/8 Hz2/8 Hz, by how much will the centripetal force applied by the tracks change by?