A model train, with a mass of 2 kg, is moving on a circular track with a radius of 4 m. If the train's kinetic energy changes from 2 j to 16 j, by how much will the centripetal force applied by the tracks change by?

1 Answer
Feb 19, 2016

It will increase 8 times, which in this case corresponds to an increase of 8N.

Explanation:

Since the kinetic energy is E_k=1/2mv^2 and increased from 2J to 16J, ie increased 8 times, it implies that the v^2 must have increased 8 times, and hence v increased sqrt8 times.
(Assuming mass remains constant.)

Now the centripetal force is given my F_c=(mv^2)/r and directed towards the centre of the circle.
So assuming the mass and radius stays the same, if v^2 increases 8 times, then F_c also increases 8 times.

Now the initial velocity was sqrt(E_k/(1/2m))=sqrt(2/(1/2xx2))=sqrt2 m//s

So initial centripetal force was Fc=(2xx2)/4=1N.

Therefore the new centripetal force will be 8 times more, ie 8N.