A model train, with a mass of $2 k g$ $2 kg$ , is moving on a circular track with a radius of $8 m$ $8 m$ . If the train's rate of revolution changes from $\frac{1}{2} H z$ $1/2 Hz$ to $\frac{2}{7} H z$ $2/7 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-03-13T10:56:39

The change in centripetal force is $= 29 N$ $=29N$

The centripetal force is

$F = m r ω^{2}$ $F=mr omega^2$

$m = 2 k g$ $m=2kg$

$r = 8 m$ $r=8m$

$Delta omega=(1/2-2/7)*2pi=3/7pirads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=2*8*(3/7pi)^2$

$=29N$

A model train, with a mass of 2 kg2kg2 kg, is moving on a circular track with a radius of 8 m8m8 m. If the train's rate of revolution changes from 1/2 Hz12Hz1/2 Hz to 2/7 Hz27Hz2/7 Hz, by how much will the centripetal force applied by the tracks change by?