A model train, with a mass of 2 kg, is moving on a circular track with a radius of 2/3 m. If the train's rate of revolution changes from 1/2 Hz to 1/5 Hz, by how much will the centripetal force applied by the tracks change by?

1 Answer
May 26, 2017

The change in centripetal force is =4.74N

Explanation:

The centripetal force is

F=mr omega^2

mass is m=2kg

radius r=2/3m

Delta omega=(1/2-1/5)*2pi=(3/5pi)rads^-1

The variation in centripetal force is

DeltaF=mr(Delta omega)^2

=2*2/3*(3/5pi)^2

=4.74N