A model train with a mass of $3 kg$ is moving along a track at $12 (cm)/s$ . If the curvature of the track changes from a radius of $5 cm$ to $8 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-05-08T10:37:48

The change in centripetal force is $=0.32N$

The centripetal force is

$F=(mv^2)/r$

mass, $m=3kg$

speed, $v=0.12ms^-1$

radius, $=(r) m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=3*0.12^2/0.05=0.86N$

$F_2=mv^2/r_2=3*0.12^2/0.08=0.54N$

$DeltaF=0.86-0.54=0.32N$

A model train with a mass of 3 kg3 kg is moving along a track at 12 (cm)/s12 (cm)/s. If the curvature of the track changes from a radius of 5 cm5 cm to 8 cm8 cm, by how much must the centripetal force applied by the tracks change?