A model train with a mass of $3 kg$ is moving along a track at $12 (cm)/s$ . If the curvature of the track changes from a radius of $5 cm$ to $24 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2018-01-02T07:26:41

The change in centripetal force is $=0.864N$

The centripetal force is

$F=(mv^2)/r$

The mass is of the train $m=3kg$

The velocity is $v=0.12ms^-1$

The radii are

$r_1=0.05m$

and

$r_2=0.24m$

The variation in the centripetal force is

$DeltaF=F_2-F_1$

The centripetal forces are

$F_1=3*0.12^2/0.05=0.864N$

$F_2=3*0.12^2/0.24=0.18N$

$DeltaF=0.864-0.18=0.684N$

A model train with a mass of 3 kg3 kg is moving along a track at 12 (cm)/s12 (cm)/s. If the curvature of the track changes from a radius of 5 cm5 cm to 24 cm24 cm, by how much must the centripetal force applied by the tracks change?