A model train with a mass of $3 kg$ is moving along a track at $15 (cm)/s$ . If the curvature of the track changes from a radius of $15 cm$ to $12 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-03-06T07:22:05

The change in centripetal force is $=0.11N$

The centripetal force is

$F=(mv^2)/r$

$m=mass=3kg$

$v=0.15ms^-1$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=3*0.15^2/0.15=0.45N$

$F_2=3*0.15^2/0.12=0.56N$

$DeltaF=0.56-0.45=0.11N$

A model train with a mass of 3 kg3 kg is moving along a track at 15 (cm)/s15 (cm)/s. If the curvature of the track changes from a radius of 15 cm15 cm to 12 cm12 cm, by how much must the centripetal force applied by the tracks change?