A model train with a mass of $3 kg$ is moving along a track at $16 (cm)/s$ . If the curvature of the track changes from a radius of $12 cm$ to $32 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-05-05T12:05:09

The change in centripetal force is $=0.4N$

The centripetal force is

$F=(mv^2)/r$

mass, $m=3kg$

speed, $v=0.16ms^-1$

radius, $=(r) m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=3*0.16^2/0.12=0.64N$

$F_2=mv^2/r_2=3*0.16^2/0.32=0.24N$

$DeltaF=0.64-0.24=0.4N$

A model train with a mass of 3 kg3 kg is moving along a track at 16 (cm)/s16 (cm)/s. If the curvature of the track changes from a radius of 12 cm12 cm to 32 cm32 cm, by how much must the centripetal force applied by the tracks change?