A model train with a mass of $3 k g$ $3 kg$ is moving along a track at $16 \frac{c m}{s}$ $16 (cm)/s$ . If the curvature of the track changes from a radius of $8 c m$ $8 cm$ to $32 c m$ $32 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-03-12T11:01:48

The change in centripetal force is $= 0.72 N$ $=0.72N$

The centripetal force is

$F = \frac{m v^{2}}{r}$ $F=(mv^2)/r$

$m = m a s s = 3 k g$ $m=mass=3kg$

$v = 0.16 m s^{- 1}$ $v=0.16ms^-1$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=3*0.16^2/0.08=0.96N$

$F_2=3*0.16^2/0.32=0.24N$

$DeltaF=0.96-0.24=0.72N$

A model train with a mass of 3 kg3kg3 kg is moving along a track at 16 (cm)/s16cms16 (cm)/s. If the curvature of the track changes from a radius of 8 cm8cm8 cm to 32 cm32cm32 cm, by how much must the centripetal force applied by the tracks change?