A model train with a mass of $3 kg$ is moving along a track at $8 (cm)/s$ . If the curvature of the track changes from a radius of $4 cm$ to $18 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-02-11T11:03:46

The change in centripetal force is $=0.12N$

The centripetal force is

$F=(mv^2)/r$

The variation in centripetal force is

$DeltaF=(mv^2)/(Delta r)$

$=(3*(0.08)^2)/(0.18-0.04)$

$=(3*0.08*0.08)/0.16$

$=0.12N$

A model train with a mass of 3 kg3 kg is moving along a track at 8 (cm)/s8 (cm)/s. If the curvature of the track changes from a radius of 4 cm4 cm to 18 cm18 cm, by how much must the centripetal force applied by the tracks change?