A model train with a mass of $3 kg$ is moving along a track at $8 (cm)/s$ . If the curvature of the track changes from a radius of $5 cm$ to $24 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2018-02-17T19:05:23

The change in centripetal force is $0.304N$

The centripetal force is

$vecF_C=(mv^2)/r*vecr$

The mass is of the train $m=3kg$

The velocity of the train is $v=0.08ms^-1$

The radii of the tracks are

$r_1=0.05m$

and

$r_2=0.24m$

The variation in the centripetal force is

$DeltaF=F_2-F_1$

The centripetal forces are

$||F_1||=3*0.08^2/0.05=0.384N$

$||F_2||=3*0.08^2/0.24=0.08N$

$DeltaF=F_2-F_1=0.384-0.08=0.304N$

A model train with a mass of 3 kg3 kg is moving along a track at 8 (cm)/s8 (cm)/s. If the curvature of the track changes from a radius of 5 cm5 cm to 24 cm24 cm, by how much must the centripetal force applied by the tracks change?