A model train, with a mass of $3 kg$ , is moving on a circular track with a radius of $8 m$ . If the train's rate of revolution changes from $1/6 Hz$ to $1/2 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-03-17T14:34:50

The centripetal force changes by $105.3N$

The centripetal force is

$F=mr omega^2$

mass is $m=3kg$

radius $r=8m$

$Delta omega=(1/2-1/6)*2pi=2/3pirads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=3*8*(2/3pi)^2$

$=105.3N$

A model train, with a mass of 3 kg3 kg, is moving on a circular track with a radius of 8 m8 m. If the train's rate of revolution changes from 1/6 Hz1/6 Hz to 1/2 Hz1/2 Hz, by how much will the centripetal force applied by the tracks change by?