A model train, with a mass of $3 kg$ , is moving on a circular track with a radius of $8 m$ . If the train's rate of revolution changes from $1/9 Hz$ to $1/2 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-06-24T07:01:30

The centripetal force changes by $=143.3N$

The centripetal force is

$F=mr omega^2$

The mass is $m=3kg$

The radius $r=8m$

The change in angular velocity is

$Delta omega=(1/2-1/9)*2pi=(7/9pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=3*8*(7/9pi)^2$

$=143.3N$

A model train, with a mass of 3 kg3 kg, is moving on a circular track with a radius of 8 m8 m. If the train's rate of revolution changes from 1/9 Hz1/9 Hz to 1/2 Hz1/2 Hz, by how much will the centripetal force applied by the tracks change by?