A model train, with a mass of $3 kg$ , is moving on a circular track with a radius of $2 m$ . If the train's rate of revolution changes from $5/8 Hz$ to $3/4 Hz$ , by how much will the centripetal force applied by the tracks change by?

Question

1450 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-26T06:34:29

The centripetal force change by $=3.7N$

The centripetal force is

$F=mr omega^2$

The mass is $m=3kg$

The radius $r=2m$

The change in angular velocity is

$Delta omega=(3/4-5/8)*2pi=(1/4pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=3*2*(1/4pi)^2$

$=3.7N$

A model train, with a mass of 3 kg3 kg, is moving on a circular track with a radius of 2 m2 m. If the train's rate of revolution changes from 5/8 Hz5/8 Hz to 3/4 Hz3/4 Hz, by how much will the centripetal force applied by the tracks change by?