A model train, with a mass of 3 kg, is moving on a circular track with a radius of 2 m. If the train's rate of revolution changes from 2/5 Hz to 3/7 Hz, by how much will the centripetal force applied by the tracks change by?

1 Answer
Mar 6, 2017

The change in centripetal force is 0.19N

Explanation:

The centripetal force is

F=mr omega^2

m=3kg

r=2m

Delta omega=(3/7-2/5)*2pi=2/35pirads^-1

The variation in centripetal force is

DeltaF=mr(Delta omega)^2

=3*2*(2/35pi)^2

=0.19N