A model train, with a mass of $3 k g$ $3 kg$ , is moving on a circular track with a radius of $5 m$ $5 m$ . If the train's kinetic energy changes from $32 j$ $32 j$ to $12 j$ $12 j$ , by how much will the centripetal force applied by the tracks change by?

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A model train, with a mass of $3 k g$ $3 kg$ , is moving on a circular track with a radius of $5 m$ $5 m$ . If the train's kinetic energy changes from $32 j$ $32 j$ to $12 j$ $12 j$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2016-02-02T17:12:29

$F_{C} = 2 \frac{K E}{r} = 2 \frac{20}{5} = 8 N$ $F_C = 2(KE)/r = 2 20/5 = 8 N$

Explanation:

Start by writing the equation for Kinetic Energy, KE:
$K E = \frac{1}{2} m v^{2}$ $KE = 1/2 mv^2$ divide by 2 on both sides
$2 K E = m v^{2}$ $2KE = mv^2$ divide by r the radius of the circular track
$2 \frac{K E}{r} = m \frac{v^{2}}{r}$ $2(KE)/r = mv^2/r$ now on the right what we have is the Centripetal Force $F_{C} = m (\frac{v^{2}}{r})$ $F_C = m(v^2/r)$ , so:
$F_{C} = 2 \frac{K E}{r} = 2 \frac{20}{5} = 8 N$ $F_C = 2(KE)/r = 2 20/5 = 8 N$

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A model train, with a mass of $3 k g$ $3 kg$ , is moving on a circular track with a radius of $5 m$ $5 m$ . If the train's kinetic energy changes from $32 j$ $32 j$ to $12 j$ $12 j$ , by how much will the centripetal force applied by the tracks change by?

1 Answer

Explanation:

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A model train, with a mass of 3kg3 kg, is moving on a circular track with a radius of 5m5 m. If the train's kinetic energy changes from 32j32 j to 12j12 j, by how much will the centripetal force applied by the tracks change by?

1 Answer

Explanation:

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A model train, with a mass of $3 k g$ $3 kg$ , is moving on a circular track with a radius of $5 m$ $5 m$ . If the train's kinetic energy changes from $32 j$ $32 j$ to $12 j$ $12 j$ , by how much will the centripetal force applied by the tracks change by?