A model train, with a mass of $3 k g$ $3 kg$ , is moving on a circular track with a radius of $8 m$ $8 m$ . If the train's rate of revolution changes from $\frac{1}{9} H z$ $1/9 Hz$ to $\frac{1}{7} H z$ $1/7 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-04-26T14:41:32

The centripetal force changes by $= 0.24 N$ $=0.24N$

The centripetal force is

$F = m r ω^{2}$ $F=mr omega^2$

mass is $m = 3 k g$ $m=3kg$

radius $r = 8 m$ $r=8m$

$Delta omega=(1/7-1/9)*2pi=(2/63pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=3*8*(2/63pi)^2$

$=0.24N$

A model train, with a mass of 3 kg3kg3 kg, is moving on a circular track with a radius of 8 m8m8 m. If the train's rate of revolution changes from 1/9 Hz19Hz1/9 Hz to 1/7 Hz17Hz1/7 Hz, by how much will the centripetal force applied by the tracks change by?