A model train, with a mass of $3 kg$ , is moving on a circular track with a radius of $1 m$ . If the train's kinetic energy changes from $21 j$ to $36 j$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2016-04-29T11:05:08

To make it simple, lets find out the relation of kinetic energy and centripetal force with the things we know:

We know: $"K.E." = 1/2momega^2r^2$

and $"centripetal force"=momega^2r$

Hence, $"K.E" = 1/2xx"centripetal force"xxr$

Note, $r$ remain constant in the course of the process.

Hence, $Delta"centripetal force" = (2Delta"K.E.")/r = (2(36-21)J)/(1m)=30N$

A model train, with a mass of 3 kg3 kg, is moving on a circular track with a radius of 1 m1 m. If the train's kinetic energy changes from 21 j21 j to 36 j36 j, by how much will the centripetal force applied by the tracks change by?